[rpls]

Hi
I know how to write a basic condition for generating hands.
For example:

(( hcp(east)>=6 and hcp(east)<=10) 
and ( (spades(east)>=7 and hcp(east,spades)>=5) 
or(hearts(east)>=7 and hcp(east,hearts)>=5) 
or(diamonds(east)>=7 and hcp(east,diamonds)>=5 ) 
or(clubs(east)>=7 and hcp(east,clubs)>=5 )))

What I dont know how to do is to add to this code a condition for either south or north also having 6 cards of spades. Is that possible?

Regards

Thanks in advance

[pescetom]

The syntax looks quite simple, so it must be something like this:

(( hcp(east)>=6 and hcp(east)<=10)
and (spades(north)=6 or spades(south)=6)
and ( (spades(east)>=7 and hcp(east,spades)>=5) 
or(hearts(east)>=7 and hcp(east,hearts)>=5) 
or(diamonds(east)>=7 and hcp(east,diamonds)>=5 ) 
or(clubs(east)>=7 and hcp(east,clubs)>=5 )))

[nullve]

pescetom, on 2018-October-12, 06:41, said:

The syntax looks quite simple, so it must be something like this:

(( hcp(east)>=6 and hcp(east)<=10)
and (spades(north)=6 or spades(south)=6)
and ( (spades(east)>=7 and hcp(east,spades)>=5) 
or(hearts(east)>=7 and hcp(east,hearts)>=5) 
or(diamonds(east)>=7 and hcp(east,diamonds)>=5 ) 
or(clubs(east)>=7 and hcp(east,clubs)>=5 )))

The "equals" symbol is '==', not '=', so make it

(( hcp(east)>=6 and hcp(east)<=10)
and (spades(north)==6 or spades(south)==6)
and ( (spades(east)>=7 and hcp(east,spades)>=5) 
or(hearts(east)>=7 and hcp(east,hearts)>=5) 
or(diamonds(east)>=7 and hcp(east,diamonds)>=5 ) 
or(clubs(east)>=7 and hcp(east,clubs)>=5 )))

.

[rpls]

nullve, on 2018-October-12, 06:55, said:

The "equals" symbol is '==', not '=', so make it

(( hcp(east)>=6 and hcp(east)<=10)
and (spades(north)==6 or spades(south)==6)
and ( (spades(east)>=7 and hcp(east,spades)>=5) 
or(hearts(east)>=7 and hcp(east,hearts)>=5) 
or(diamonds(east)>=7 and hcp(east,diamonds)>=5 ) 
or(clubs(east)>=7 and hcp(east,clubs)>=5 )))

.

I just tried the last code and it worked perfectly

I wanna thank both of you for your help

Regards