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A comment to P(4333 in all hands)

#1 User is offline   carl3 

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Posted 2024-March-02, 08:22

P(4333 in all hands)= 4! (13o4 13o3 13o3 13o3) (9o3 10o4 10o3 10o3) (6o3 6o3 7o4 7o3) /(52o13 39o13 26o13) = !/1074. (Smerriman gets the same but I cannot understand how he reasons.) What is really interesting (and the motivation to post this as a separate topic) is how close this is to the results from the simulations. It says that shufflng by computers works very well.
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