finally get a hand where Gerber applies and Ben screws it up
responded 4♦ 0 or 4 aces as i have 1 that means 0
but it had 3 aces. if it shows 3 aces i bid 7N
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Ben gives wrong response to Gerber
#2
Posted 2026-June-10, 14:25
From a Ben point of view, I seem to remember this bug was already documented here.
Seeing as Lorserker has miraculously resuscitated, maybe he could confirm
From a bridge point of view, I think Gerber was (yet again) inappropriate.
You know there are 32-34 points on the line and you have 6 running diamonds.
6NT looks almost inevitable and does not depend upon number of Aces (barring the freak of opps holding 2 Aces and no other honour, even then they have to find both).
But 7♦ also looks likely and well worth investigating.
Seeing as Lorserker has miraculously resuscitated, maybe he could confirm
From a bridge point of view, I think Gerber was (yet again) inappropriate.
You know there are 32-34 points on the line and you have 6 running diamonds.
6NT looks almost inevitable and does not depend upon number of Aces (barring the freak of opps holding 2 Aces and no other honour, even then they have to find both).
But 7♦ also looks likely and well worth investigating.
#3
Posted 2026-June-10, 16:43
I thought i saw that all bids above 3NT are not defined. If so hard to bid slams scientifically.
Sarcasm is a state of mind
#4
Posted 2026-June-10, 17:37
pescetom, on 2026-June-10, 14:25, said:
From a bridge point of view, I think Gerber was (yet again) inappropriate.
You know there are 32-34 points on the line and you have 6 running diamonds.
6NT looks almost inevitable and does not depend upon number of Aces (barring the freak of opps holding 2 Aces and no other honour, even then they have to find both).
But 7♦ also looks likely and well worth investigating.
You know there are 32-34 points on the line and you have 6 running diamonds.
6NT looks almost inevitable and does not depend upon number of Aces (barring the freak of opps holding 2 Aces and no other honour, even then they have to find both).
But 7♦ also looks likely and well worth investigating.
Why is Gerber inappropriate when there is a chance you are missing 2 aces, especially playing with Ben? OK, one reason would be that Ben makes random responses to Gerber. BTW, sometimes you won't have 12 tricks even if the opponents don't cash their 2 aces.
#6
Posted Today, 14:30
johnu, on 2026-June-10, 17:37, said:
Why is Gerber inappropriate when there is a chance you are missing 2 aces
We've been through this before, here is what I wrote at the time
Quote
#
# Does it make sense to check if we are missing 2 cashing tricks?
#
produce 1000
Nmin=15
Nmax=17
Smin=17
Smax=17
Open1NT = shape(north, any 4333 + any 4423 + any 5332) and hcp(north)>=Nmin and hcp(north)<=Nmax
Raiseto6NT = shape(south, any 4333 + any 4423) and hcp(south)>=Smin and hcp(south)<=Smax
EtopS = top2(east,spades)
EtopH = top2(east,hearts)
EtopD = top2(east,diamonds)
EtopC = top2(east,clubs)
WtopS = top2(west,spades)
WtopH = top2(west,hearts)
WtopD = top2(west,diamonds)
WtopC = top2(west,clubs)
EWaces = aces(east) + aces(west)
NSaces = aces(north) + aces(south)
EWkings = kings(east) + kings(west)
EWhcp = hcp(east) + hcp(west)
OffAKany = ((EWaces == 1) and (EWkings == 1))
OffAKsame = (EtopS + WtopS == 2) or (EtopH + WtopH == 2) or (EtopD + WtopD == 2) or (EtopC + WtopC == 2)
action frequency "EW hcp" (EWhcp,0,9), frequency "EW Aces" (EWaces,0,4), frequency "EW have an A and a K" (OffAKany,0,1), frequency "EW have AK in same suit" (OffAKsame,0,1)
condition Open1NT and Raiseto6NT
#### for debug or skeptics, uncomment and reduce Produce to a small number
#action printes (" EtopS: ", EtopS, " EtopH: ", EtopH," EtopC: ", EtopC," EtopD: ", EtopD," WtopS: ", WtopS," WtopH: ", WtopH," WtopC: ", WtopC," WtopD: ", WtopD, " OffAKsame:", OffAKsame, " NSaces:", NSaces, " EWaces:", EWaces, \n), printew
# Does it make sense to check if we are missing 2 cashing tricks?
#
produce 1000
Nmin=15
Nmax=17
Smin=17
Smax=17
Open1NT = shape(north, any 4333 + any 4423 + any 5332) and hcp(north)>=Nmin and hcp(north)<=Nmax
Raiseto6NT = shape(south, any 4333 + any 4423) and hcp(south)>=Smin and hcp(south)<=Smax
EtopS = top2(east,spades)
EtopH = top2(east,hearts)
EtopD = top2(east,diamonds)
EtopC = top2(east,clubs)
WtopS = top2(west,spades)
WtopH = top2(west,hearts)
WtopD = top2(west,diamonds)
WtopC = top2(west,clubs)
EWaces = aces(east) + aces(west)
NSaces = aces(north) + aces(south)
EWkings = kings(east) + kings(west)
EWhcp = hcp(east) + hcp(west)
OffAKany = ((EWaces == 1) and (EWkings == 1))
OffAKsame = (EtopS + WtopS == 2) or (EtopH + WtopH == 2) or (EtopD + WtopD == 2) or (EtopC + WtopC == 2)
action frequency "EW hcp" (EWhcp,0,9), frequency "EW Aces" (EWaces,0,4), frequency "EW have an A and a K" (OffAKany,0,1), frequency "EW have AK in same suit" (OffAKsame,0,1)
condition Open1NT and Raiseto6NT
#### for debug or skeptics, uncomment and reduce Produce to a small number
#action printes (" EtopS: ", EtopS, " EtopH: ", EtopH," EtopC: ", EtopC," EtopD: ", EtopD," WtopS: ", WtopS," WtopH: ", WtopH," WtopC: ", WtopC," WtopD: ", WtopD, " OffAKsame:", OffAKsame, " NSaces:", NSaces, " EWaces:", EWaces, \n), printew
#7
Posted Today, 16:02
pescetom, on 2026-June-13, 14:30, said:
We've been through this before, here is what I wrote at the time 
Also, in real life, many players will upgrade very good 14 counts to 1NT. So there are a lot more hands where 2 aces are missing. But why not ask for aces if that is part of your system, even if missing 2 aces doesn't happen often?
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