[MinorKid]

Case 1:

---

7♦: "I am making 7♦ !"

Case 2:

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1♦: 11~15 HCP, 2+♦

These cases are not duplicates, of course there could be different hands among the three players.

[RunemPard]

7♦ by N is a preempt? This must be that so called goulash with agreements about this before hand.

In that case I will go with the obvious 8♦.

[RunemPard]

On a more serious note...I pass. Although double will most likely take the hand down...but I am paranoid any time I play in these tournies. Partner probably sitting on a ♠ void and the other opp has the other ♠ and void in our other suit...

Evilness at it's best.

[Cyberyeti]

There's a case for partner having 12 diamonds and A♥ and RHO having 13 spades, but I'm not sure I'm prepared to take the risk of RHO only having 11 or 12 of them

[MinorKid]

I trust my partner for making 7♦. If he has AKQJxxxxxxxx and a small card, he will bid 6♦.

But WTF is 7♠??

Cyberyeti, on 2012-September-20, 02:30, said:

There's a case for partner having 12 diamonds and A♥ and RHO having 13 spades, but I'm not sure I'm prepared to take the risk of RHO only having 11 or 12 of them

Partner could be 12 ♦ with the ♠A

[CSGibson]

obvious 7N bids, as long as its from my side (god, I hope lefty has a spade void...and no aces...)

[gwnn]

double (negative)

[MinorKid]

How about case 2 ?
Are you sure that West holds ♠ void this time?

[rogerclee]

How can you think LHO is likely at all to have a spade void? RHO's 7S bid doesn't even guarantee holding 10 spades, let alone 13.

[CSGibson]

To clarify, I was joking. At the table I would make Gwnn's negative double.

[gszes]

MinorKid, on 2012-September-20, 02:01, said:

Case 1:

---

7♦: "I am making 7♦ !"

Case 2:

---

1♦: 11~15 HCP, 2+♦

These cases are not duplicates, of course there could be different hands among the three players.

case 1 PASS not out of fear-- but because you want to convey to p a willingness to try 7n
if they have the spade A. This means any other hand just x 7s even with zero. It is far too
important to leave us a chance of making 7n to use x in any other fashion even if the
situation is going to be rare. Note that our hand can be far weaker overall to make this
pass (ie) void Axxxxx x Axxxxx

case 2 a case can be made for treating this hand the same as hand 1. The number of hands
(after a 1d bid) that would meet the requirements for a try for 7n can probably be counted using
no more than your fingers and toes. This extremely low % means it is not mathematically worth
using this way and IMO pass here would merely mean too weak to x 7s and X is a plain old
panalty x (this is what i would choose whatever top club your partnership leads looking for count).

a direct bid of 7n in either case is just a bid designed to get rid of your current partner.

[Antrax]

gszes, do you think it's often people bid 7♠ missing the ace of spades? I mean, this is goulash so any discussion of probability is silly to begin with, but ignoring that.

[MrAce]

CSGibson, on 2012-September-22, 09:43, said:

To clarify, I was joking. At the table I would make Gwnn's negative double.

You scared me for a second !! I was about to call 911 and send people to your house

[gwnn]

Next week on Awkward. : 1NT-p-7NT-p;p-x-xx-??
pass or pull??

[MinorKid]

gszes, on 2012-September-22, 09:49, said:

case 1 PASS not out of fear-- but because you want to convey to p a willingness to try 7n
if they have the spade A. This means any other hand just x 7s even with zero. It is far too
important to leave us a chance of making 7n to use x in any other fashion even if the
situation is going to be rare. Note that our hand can be far weaker overall to make this
pass (ie) void Axxxxx x Axxxxx

case 2 a case can be made for treating this hand the same as hand 1. The number of hands
(after a 1d bid) that would meet the requirements for a try for 7n can probably be counted using
no more than your fingers and toes. This extremely low % means it is not mathematically worth
using this way and IMO pass here would merely mean too weak to x 7s and X is a plain old
panalty x (this is what i would choose whatever top club your partnership leads looking for count).

a direct bid of 7n in either case is just a bid designed to get rid of your current partner.

Case 1.
Partner has ♦AKQJxxxxxxxx ♠A OR ♦AKQJxxxxxxxx ♥A
I guess most pairs would like to defend 7♠ or 7♠X . 7NT will make when he has the first hand or RHO holds all thirteen diamonds, which is not a big chance.

However, if you have (void Axxxxx x Axxxxx) instead than 7NT will make for sure because your partner must have the ♠A .




Case 2 is a bit different from case 1.
This time you judge your RHO, given that 7♠ is going to make.
You can calculate that either we can make 7NT or your partner were underualified for the 1♦.